Thread: [Help]Or statement

Originally Posted by Mikri Maus

How to get a program like this work?

Code:

#include <stdio.h>
#include <stdlib.h>

int main()
{
int a,b,c;
-1<a<10 or a==50;
-2<b<11 or b==51;
c=a+b;

do{
a=rand();
b=rand();
printf("%d,%d,%d",a,b,c);
}while(1==1);
}

Well, at the very least you'll need to use valid C code. A better description of the problem would be useful too...

Welcome to the forum.

Where are the if statements??
This section

Code:

-1<a<10 or a==50;
-2<b<11 or b==51;
c=a+b;

should be like

Code:

if( ( -1 < a && a < 10 ) || a == 50)
{
    do_something;
}

You need to do the same with the second if statement.
The "||" operator is the OR and the "&&" operator, the AND.
You see, you want your condition to be true if, a is larger than -1 (-1 < a) AND less than 10 (a < 10) OR a to be equal with 50 (a == 50).

You need to do this in order to take random numbers

Code:

srand( (unsigned int)time ( NULL ) );

You should check your indent style as well!

However, you are trying to apply your logic (the if statements), before giving variables a value!! As a result, you need to move your logic, in order o be executed after you give your variables values!

You have a loop that will be executed as long as 1 == 1, which means forever. Not good. That is an infinite loop and will cause your program to run forever!

Let's see another example:
Assume that I want to have a loop, that will be executed again and again, as long as, the variable named "a" has a value less than 5 or equal to 6. Initial variable of "a" is zero. Every time the loop is executed, add 2 to variable "a". Print the final value of "a".
Here is an example solution with comments.

Code:

#include <stdio.h>
#include <stdlib.h>
 
/* void states that we receive no arguments from cmd */
int main(void)
{
    /* Initial value for a. */
    int a = 0;
    
    /* We know that our loop is going to be executed at least once,
       so a do-while loop is ok.
     */
    do{
        /* Every time the loop gets executed, add 2 to a. */
        a = a + 2;
        
        /* Conitnue looping, while a is less than 5 OR a is equal to 6*/
    }while(a < 5 || a == 6);
    
    /* Print value of a.*/
    printf("a = %d\n", a);
    
    /* Exit the program. */
    return 0;
}

I suggest you run this code in a paper with a pen and see what the value of a will be. Then run the code to test.